![]() So every position in the password can contain one of the 192 characters. On the german keyboard, there can be 192 different characters to be entered in a password, this is |Z| = 192. This makes Z = the alphabet on which to operate. Valid assumptions included things like “how many characters can be entered using the (german version of the) keyboard”. Of course, I applied stupid assumptions, as “you can try as often as you want” and “each try lasts 1 second until you get the result”. Here are my thoughts, just for your entertainment:īecause it’s not possible to “uncrypt” a password that has been crypted one time, I can only try a passphrase and see if it’s valid (first crypt it, then compare). ![]() Many years ago, while sitting at the… don’t mind… I had the idea of calculating if a password could be “guessed” by brute force until our sun explodes.
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